You are drawing from a normally distributed random variable (RV) $X \sim N(0, 1)$ once a day. What is the approximate expected number of days until you get a value greater than 2?

Therefore, $P(X > 2) = 1 - 0.977 = 0.023$ for any given day. Since each day's draws are independent, the expected time until drawing an $X > 2$ follows a geometric distribution, with $p = 0.023$. Letting $T$ be a random variable denoting the number of days, we have the following: