8 Interactive Brokers SQL Interview Questions (Updated 2025)

Updated on

April 24, 2025

Interactive Brokers employees use SQL often for analyzing trading patterns and managing large databases of client trading histories. That's the reason behind why Interactive Brokers covers SQL problems during interviews for Data Analyst, Data Science, and BI jobs.

So, to help you study for the Interactive Brokers SQL interview, we'll cover 8 Interactive Brokers Group SQL interview questions – scroll down to start solving them!

Interactive Brokers SQL Interview Questions

8 Interactive Brokers Group SQL Interview Questions

SQL Question 1: Analyze Trade Volumes

Interactive Brokers is a preeminent brokerage firm. Consider a hypothetical situation where you are given access to trading data that outlines each trade executed on the platform. In this case, you may want to analyze trade volumes for all stocks on a month-by-month basis and compare it with the previous month trade volume.

Create a SQL query using window functions to retrieve the trade volume per stock symbol per month, along with the percentage difference from the previous month's volume.

trades Example Input:

trade_idtrade_datesymbolvolume
1112022-06-01AAPL1000
2222022-06-15AAPL2000
3332022-06-29GOOG1200
4442022-07-01AAPL3000
5552022-07-02GOOG3000
6662022-07-20GOOG1500
7772022-08-01AAPL2500
8882022-08-15AAPL2000
9992022-08-30AAPL1500

Example Output:

mthsymboltrade_volumedifference
JuneAAPL3000-
JuneGOOG1200-
JulyAAPL30000
JulyGOOG4500275.00%
AugustAAPL6000100.00%
AugustGOOG0-100%

Answer:

WITH monthly_volumes AS ( SELECT date_trunc('month', trade_date) as mth, symbol, sum(volume) as trade_volume FROM trades GROUP BY mth, symbol ) SELECT to_char(mth, 'Month') as mth, symbol, trade_volume, COALESCE( ((trade_volume - lag(trade_volume) OVER (PARTITION BY symbol ORDER BY mth)) / lag(trade_volume) OVER (PARTITION BY symbol ORDER BY mth)) * 100, '-' ) as difference FROM monthly_volumes ORDER BY mth, symbol;

This query first aggregates the total trading volume for each stock symbol on a month-by-month basis. Then it uses a window function (the lag function) to calculate the trade volume difference between the current month and the previous month, expressed as a percentage. The COALESCE function is used to handle cases where there is no previous month data by returning '-' as the value. The result is sorted by month and symbol for ease of reading.

For more window function practice, try this Uber SQL problem within DataLemur's interactive SQL code editor:

Uber SQL problem

SQL Question 2: Department Salaries

Imagine there was a table of Interactive Brokers employee salaries, along with which department they were in. Write a query to compare the average salary of employees in each department to the company's average salary for March 2024. Return the comparison result as 'higher', 'lower', or 'same' for each department. Display the department ID, payment month (in MM-YYYY format), and the comparison.

Write a SQL query for this interview question directly within the browser on DataLemur:

Department vs. Company Salary

The solution is LONG – 30+ lines of SQL. You can find a detailed solution here: Department vs. Company Salary.

SQL Question 3: How does the RANK() window function differ from DENSE_RANK()?

While both RANK() and DENSE_RANK() are used to rank rows, the key difference is in how they deal with ties.

RANK(): When there's a tie, RANK() leaves a gap in the ranking. For example, if three rows are tied for 2nd place, the RANK() function will assign a rank of 2 to the first of these rows, a rank of 3 to the 2nd row in the tie, and a rank of 4 to the the 3rd tie.

DENSE_RANK(): For ties, DENSE_RANK() does not leave a gap in the ranking. Instead, it assigns the same rank to all tied rows, and then makes the next row 1 bigger. Confusing, I know, but here's an example to make it more clear: if three rows are tied for 3rd place, the DENSE_RANK() function will assign a rank of 3 to all three rows, and then assign a rank of 4 to the next row.

Suppose we had data on how many deals different salespeople at Interactive Brokers:

WITH data AS ( SELECT 'Akash' AS name, 50 AS deals_closed UNION ALL SELECT 'Brittany', 50 UNION ALL SELECT 'Carlos', 40 UNION ALL SELECT 'Dave', 30 UNION ALL SELECT 'Eve', 30 UNION ALL SELECT 'Farhad', 10 )

To rank these salespeople, we could execute the following query:

SELECT name, deals_closed, RANK() OVER (ORDER BY deals_closed DESC) as rank, DENSE_RANK() OVER (ORDER BY deals_closed DESC) as dense_rank FROM interactive_brokers_sales;

The result of this query would be:

namedeals_closedrankdense_rank
Akash5011
Brittany5021
Carlos4032
Dave4043
Eve3053
Farhad1064

As you can see, the RANK() function assigns a rank of 1 to the first row (Akash), a rank of 2 to the second row (Brittany), and so on. In contrast, the DENSE_RANK(), gives both Akash and Brittany a rank of 1, since they are tied, then moves on to rank 2 for Carlos.

Interactive Brokers Group SQL Interview Questions

SQL Question 4: Active Traders Filter

Interactive Brokers is interested in identifying its active traders who have carried out more than 10 trades in the last month and have a total balance of over $50000. Create a SQL query to find out these traders.

traders Example Input:
trader_idfull_nameaccount_balance
1054John Doe60000
1873Jane Smith40000
2950James White75000
3852Emily Black85700
4901Michael Green30500
trades Example Input:
trade_idtrader_idtrade_datetrade_amount
6171105406/08/2022 00:00:005000
7802187306/10/2022 00:00:007000
5293105406/18/2022 00:00:004000
6352105406/25/2022 00:00:0012000
4517187306/30/2022 00:00:003000
9325105407/02/2022 00:00:007000
6832295007/05/2022 00:00:008000
1191105407/06/2022 00:00:005500
0342385207/10/2022 00:00:0010000
4318105407/12/2022 00:00:006000
9275385207/15/2022 00:00:009000
9820105407/18/2022 00:00:007800
0920295007/26/2022 00:00:006800

Answer:

SELECT t.full_name, count(r.trade_id) as total_trades, t.account_balance FROM traders t JOIN trades r ON t.trader_id = r.trader_id WHERE r.trade_date BETWEEN date_trunc('month', CURRENT_DATE - interval '1 month') AND CURRENT_DATE GROUP BY t.trader_id HAVING count(r.trade_id) > 10 AND t.account_balance > 50000;

This query first joins the traders and trades tables on the trader_id. It then filters the trades to only those that have occurred in the last month using the WHERE clause. The GROUP BY clause groups the results by the trader_id and the HAVING clause filters the results to only show the traders who carried out more than 10 trades in the last month and have a total balance of over $50000.

SQL Question 5: Could you explain what a self-join is and provide examples of when it might be used?

A self-join is a JOIN operation in which a single table is joined to itself. To perform a self-join, you must specify the table name twice in the FROM clause, giving each instance a different alias. You can then join the two instances of the table using a JOIN clause, and specify the relationship between the rows in a WHERE clause.

Think of using a self-joins whenever your data analysis involves analyzie pairs of the same things, like comparing the salaries of employees within the same department, or identifying pairs of products that are frequently purchased together (which you can do in this real SQL question from a Walmart interview).

For another self-join example, suppose you were conducting an HR analytics project and needed to examine how frequently employees within the same department at Interactive Brokers interact with one another, you could use a self-join query like the following to retrieve all pairs of Interactive Brokers employees who work in the same department:

SELECT e1.name AS employee1, e2.name AS employee2 FROM interactive_brokers_employees AS e1 JOIN interactive_brokers_employees AS e2 ON e1.department_id = e2.department_id WHERE e1.id <> e2.id;

This query returns all pairs of Interactive Brokers employees who work in the same department, and excludes pairs where the employee's id is the same (since this would represent the same Interactive Brokers employee being paired with themselves).

SQL Question 6: Find the Largest Transaction for Each Client

Interactive Brokers is an electronic brokerage firm that deals with various financial services like stock trading, futures contracts, and more. Let's assume we have two tables, Clients (which maintains the client's details) and Transactions (which maintains all transactions details). Based on the provided data, the task is to find the client who made the largest transaction on each day.

Clients Example Input:
client_idclient_name
1201Alice
2506Bob
3693Cathy
4517Dan
Transactions Example Input:
transaction_idclient_idtransaction_dateamount
9238120106/08/202211000
6964250606/08/202218000
5079120106/09/20229500
8103369306/10/202216000
4304451706/10/202220000

We anticipate the output to have the date, client_id, client_name, and the maximum transaction amount for that day.

Answer:

SELECT T.transaction_date, T.client_id, C.client_name, T.max_amount FROM ( SELECT transaction_date, client_id, MAX(amount) AS max_amount FROM Transactions GROUP BY transaction_date, client_id ) AS T JOIN Clients C ON T.client_id = C.client_id ORDER BY T.transaction_date, T.max_amount DESC;

This query first finds the maximum transaction for each client on each day from the Transactions table. It then joins this result with the Clients table to get the corresponding client name. The result is ordered by transaction_date and in the descending order of the transaction amount.

SQL Question 7: Can you explain the distinction between an inner and a full outer join?

An inner join only includes rows from both tables that satisfy the join condition, whereas a full outer join includes all rows from both tables, regardless of whether they match the join condition or not.

To demonstrate each kind, Imagine you were working on a Advertising Analytics project at Interactive Brokers and had two database tables: an Advertising_Campaigns table that contains data on Google Ads keywords and their bid amounts, and a Sales table with information on product sales and the Google Ads keywords that drove those sales.

An INNER JOIN retrieves rows from both tables where there is a match in the shared key or keys. For example, an INNER JOIN between the Advertising_Campaigns table and the Sales table could be performed using the keyword column as the shared key. This would retrieve only the rows where the keyword in the Advertising_Campaigns table matches the keyword in the Sales table.

A FULL OUTER JOIN retrieves all rows from both tables, regardless of whether there is a match in the shared key or keys. If there is no match, NULL values will be returned for the columns of the non-matching table.

SQL Question 8: Finding Account Holders Residing in California

Interactive Brokers would like to target new promotional activities to clients residing in California. As a data analyst, your task is to filter down the customer database to find those customers whose addresses contain the string 'CA' (abbreviation for California).

customer Example Input:
customer_idfirst_namelast_nameaccount_balanceaddress
1001JohnDoe10000123 Main St, Los Angeles, CA
1002JaneSmith20000456 Pine Ave, New York, NY
1003TomBrown15000789 Oak St, San Francisco, CA
1004EmmaJohnson12000321 Willow Dr, Boston, MA
1005JackHill8000654 Cherry Ln, Los Angeles, CA

Your query is expected to produce the following output:

Example Output:
customer_idfirst_namelast_nameaccount_balanceaddress
1001JohnDoe10000123 Main St, Los Angeles, CA
1003TomBrown15000789 Oak St, San Francisco, CA
1005JackHill8000654 Cherry Ln, Los Angeles, CA

Answer:

SELECT * FROM customer WHERE address LIKE '%CA%';

This query filters the customer table to find all customers residing in California. Here, we use the SQL LIKE operator with the wildcard character (%) before and after 'CA' to match any address that contains the string 'CA'. Thus, it will return all records where the address field contains 'CA'.

Read about Interactive Broker's API solutions.

Interactive Brokers SQL Interview Tips

The best way to prepare for a SQL interview, besides making sure you have strong SQL fundamentals, is to practice a ton of real SQL questions that were asked in recent job interviews. Besides solving the above Interactive Brokers SQL interview questions, you should also solve the 200+ FAANG SQL Questions on DataLemur which come from companies like Facebook, Google and unicorn tech startups. DataLemur SQL Interview Questions

Each SQL question has hints to guide you, step-by-step solutions and most importantly, there's an interactive coding environment so you can right in the browser run your SQL query and have it executed.

To prep for the Interactive Brokers SQL interview it is also wise to solve SQL problems from other stock exchange & brokerage companies like:

In case your SQL skills are weak, forget about diving straight into solving questions – strengthen your SQL foundations with this SQL tutorial for Data Scientists & Analysts.

DataLemur SQL tutorial

This tutorial covers SQL concepts such as aggregate window functions and LEAD/LAG window functions – both of which pop up often during Interactive Brokers SQL interviews.

Interactive Brokers Group Data Science Interview Tips

What Do Interactive Brokers Data Science Interviews Cover?

Besides SQL interview questions, the other topics tested in the Interactive Brokers Data Science Interview include:

  • Probability & Statistics Questions
  • Python or R Coding Questions
  • Product-Sense Questions
  • ML Interview Questions
  • Behavioral & Resume-Based Questions

Interactive Brokers Data Scientist

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