At Option Care Health, SQL does the heavy lifting for analyzing complex healthcare datasets for insights into patient care trends and managing large, dynamic databases for real-time patient data accessibility. So, it shouldn't surprise you that Option Care Health almost always evaluates jobseekers on SQL problems in interviews for Data Analyst, Data Science, and BI jobs.
So, to help you prepare for the Option Care Health SQL interview, we've curated 8 Option Care Health SQL interview questions in this blog.
Option Care Health is a leading provider of home infusion services and home healthcare services. As a data analyst, identify the top 10 "VIP" patients based on the frequency of healthcare services used and amount of spending in the last 6 months. Assume we have a patient database and a transaction database.
patients
Example Input:patient_id | first_name | last_name | date_of_birth |
---|---|---|---|
1 | John | Doe | 01/01/1955 |
2 | Jane | Smith | 02/02/1965 |
3 | Mary | Johnson | 03/03/1975 |
4 | James | Brown | 04/04/1985 |
transactions
Example Input:transaction_id | patient_id | service_id | transaction_date | amount |
---|---|---|---|---|
10001 | 1 | 1001 | 01/01/2022 | $500 |
10002 | 2 | 1002 | 02/02/2022 | $1000 |
10003 | 1 | 1001 | 03/03/2022 | $300 |
10004 | 2 | 1002 | 04/04/2022 | $800 |
10005 | 1 | 1001 | 05/05/2022 | $700 |
10006 | 3 | 1003 | 06/06/2022 | $2000 |
10007 | 4 | 1002 | 07/07/2022 | $1500 |
10008 | 2 | 1002 | 08/08/2022 | $1200 |
10009 | 1 | 1001 | 09/09/2022 | $400 |
SELECT p.patient_id, p.first_name, p.last_name, COUNT(t.transaction_id) as frequency, SUM(t.amount) as total_spending FROM patients p JOIN transactions t ON p.patient_id = t.patient_id WHERE t.transaction_date >= NOW() - INTERVAL '6 months' GROUP BY p.patient_id, p.first_name, p.last_name ORDER By total_spending DESC, frequency DESC LIMIT 10;
This query joins the patients
and transactions
tables on the patient_id
field. It then filters the transactions to the last 6 months. The GROUP BY
clause is used to aggregate the data by each patient. The ORDER BY
clause sorts the patients by total spending in descending order, and then by frequency in descending order to get the top 10 VIP patients.
To solve a related customer analytics question on DataLemur's free online SQL code editor, try this recently asked Microsoft SQL interview question:
Discover how Option Care Health is harnessing the power of Palantir's artificial intelligence to enhance patient care and streamline operations! Understanding their innovative approach can provide you with a deeper insight into how healthcare companies are evolving in today's tech-driven world.
Given a table of Option Care Health employee salaries, write a SQL query to find the 2nd highest salary among all employees.
employees
Example Input:employee_id | salary |
---|---|
1 | 2500 |
2 | 800 |
3 | 1000 |
4 | 1200 |
second_highest_salary |
---|
1200 |
Try this question and run your code right in the browser:
SELECT MAX(salary) AS second_highest_salary FROM employee WHERE salary < ( SELECT MAX(salary) FROM employee );
You can find a step-by-step solution with hints here: 2nd Highest Salary.
Stored procedures are a lot like functions in programming. They're used to encapsulate and organize business logic into one unit of code, and they can accept multiple input parameters and return multiple output values.
For example, if you were a Data Analyst at Option Care Health working on a HR analytics project, you might create a stored procedure to calculate the average salary for a given department:
CREATE FUNCTION get_avg_salary(department_name TEXT) RETURNS NUMERIC AS $BODY$ BEGIN RETURN (SELECT AVG(salary) FROM option_care_health_employees WHERE department = department_name); END; $BODY$ LANGUAGE 'plpgsql';
To call this stored procedure and find the average salary for the Data Analytics department you'd write the following query:
SELECT get_avg_salary('Data Analytics');
Option Care Health is a home infusion services provider. Let's assume that the company wants to analyze its data on injections administered per pharmacy on a monthly basis. The task is to write a SQL query to calculate the average number of injections per pharmacy each month.
Here are the sample tables:
pharmacy_injections
Example Input:injection_id | pharmacy_id | date_administered | patient_id |
---|---|---|---|
1 | 101 | 06/01/2022 00:00:00 | 1234 |
2 | 101 | 06/02/2022 00:00:00 | 2345 |
3 | 202 | 06/10/2022 00:00:00 | 3467 |
4 | 202 | 06/20/2022 00:00:00 | 4568 |
5 | 303 | 07/01/2022 00:00:00 | 5679 |
6 | 303 | 07/02/2022 00:00:00 | 6789 |
7 | 303 | 07/03/2022 00:00:00 | 7890 |
month | year | pharmacy_id | avg_injections |
---|---|---|---|
6 | 2022 | 101 | 2 |
6 | 2022 | 202 | 2 |
7 | 2022 | 303 | 3 |
Here's a PostgreSQL query to calculate the average number of injections per pharmacy each month:
SELECT EXTRACT(MONTH FROM date_administered) as month, EXTRACT(YEAR FROM date_administered) as year, pharmacy_id, COUNT(*) / COUNT(DISTINCT patient_id) as avg_injections FROM pharmacy_injections GROUP BY year, month, pharmacy_id ORDER BY year, month, avg_injections DESC;
This query first extracts the month and year from the date_administered
column, then groups the data by year, month and pharmacy_id
. It calculates the count of injections divided by the count of distinct patients to find the average number of injections administered per pharmacy each month. The results are sorted by year, month, and average injections in descending order.
Pro Tip: Window functions are a frequent SQL interview topic, so practice every window function problem on DataLemur
FOREIGN KEY
constraint?A FOREIGN KEY
is a field in a table that references the PRIMARY KEY
of another table. It creates a link between the two tables and ensures that the data in the FOREIGN KEY
field is valid.
For example, if you have a table of Option Care Health customers and an orders table, the customer_id column in the orders table could be a FOREIGN KEY
that references the id column (which is the primary key) in the Option Care Health customers table.
The FOREIGN KEY
constraint helps maintain the integrity of the data in the database by preventing the insertion of rows in the FOREIGN KEY
table that do not have corresponding entries in the PRIMARY KEY
table. It also enforces the relationship between the two tables and prevents data from being deleted from the PRIMARY KEY
table if it is still being referenced in the FOREIGN KEY
table.
Option Care Health is trying to analyze the prescription behavior of its patients and their adherence to the prescribed medication over time. With a SQL data structure consisting of two tables: patients
and prescriptions
, they want to determine which drug has been prescribed the most and monitor whether there are any changes based on gender or age.
Patients table stores their basic information, and Prescriptions
table contains information on all patients' prescription data.
Patients
Example Input:patient_id | gender | age |
---|---|---|
1 | M | 45 |
2 | F | 57 |
3 | M | 29 |
4 | F | 36 |
5 | M | 62 |
Prescriptions
Example Input:prescription_id | patient_id | drug | prescribe_date |
---|---|---|---|
101 | 1 | Lisinopril | 2022-05-06 |
102 | 2 | Atorvastatin | 2022-05-07 |
103 | 3 | Metformin | 2022-05-10 |
104 | 4 | Atorvastatin | 2022-05-08 |
105 | 1 | Metformin | 2022-06-08 |
Write a PostgreSQL query to find the most prescribed drug and check the distribution by gender and age.
SELECT drug, COUNT(*) AS count, (SELECT COUNT(*) FROM Patients WHERE gender = 'M' AND patient_id IN (SELECT patient_id FROM Prescriptions WHERE drug = P.drug)) AS male_count, (SELECT COUNT(*) FROM Patients WHERE gender = 'F' AND patient_id IN (SELECT patient_id FROM Prescriptions WHERE drug = P.drug)) AS female_count, (SELECT AVG(age) FROM Patients WHERE patient_id IN (SELECT patient_id FROM Prescriptions WHERE drug = P.drug)) AS average_age FROM Prescriptions P GROUP BY drug ORDER BY count DESC LIMIT 1;
With the PostgreSQL query, we are counting the total number of prescription occurrences for each drug and also categorizing them by gender. At the same time, we calculate the average age of the patients being prescribed each drug. The result is ordered by prescription count in descending order only showing the most prescribed drug. This analysis helps us understand which medications are the most popular among patients and how age and gender are factors.
BETWEEN
is used to select rows that match a range of values, whereas the IN
operator checks for values in a specified list of values.
For example, say you were a Data Analyst at Option Care Health and had a table of advertising campaign data.
To find campaigns with between 10k in spend, you could use BETWEEN
:
SELECT * FROM option_care_health_ad_campaigns WHERE spend BETWEEN 500 AND 10000;
To find ad campaigns that were run on Facebook and Google's Display Network, you could use IN
:
SELECT * FROM option_care_health_ad_campaigns WHERE ad_platform IN ("fb", "google_display");
You are given a database of the patients of Option Care Health. Write an SQL query that filters the database to find all records where the condition
column contain the term 'diabetes' (regardless of case sensitivity).
The patients
table is structured as follows:
patients
Example Input:patient_id | first_name | last_name | registered_date | condition |
---|---|---|---|---|
1001 | John | Doe | 02/11/2019 00:00:00 | Diabetes |
1002 | Jane | Smith | 08/20/2020 00:00:00 | Heart Disease |
1003 | Sarah | Lee | 12/09/2018 00:00:00 | High Blood Pressure |
1004 | Paul | Jackson | 03/25/2021 00:00:00 | diabetes |
1005 | Roger | Williams | 07/15/2019 00:00:00 | Diabetes, High Blood Pressure |
Given this input, your output should look similar to this:
patient_id | first_name | last_name | registered_date | condition |
---|---|---|---|---|
1001 | John | Doe | 02/11/2019 00:00:00 | Diabetes |
1004 | Paul | Jackson | 03/25/2021 00:00:00 | diabetes |
1005 | Roger | Williams | 07/15/2019 00:00:00 | Diabetes, High Blood Pressure |
SELECT * FROM patients WHERE LOWER(condition) LIKE '%diabetes%';
The PostgreSQL query uses the LIKE
keyword to match text values against a pattern using wildcards. Here, the '%' is a wildcard character that matches zero or more characters. The LOWER(condition)
function converts the condition to lower case before checking with the LIKE
keyword, ensuring the case-insensitive match to 'diabetes'. This query will return all records in the patients
table where the condition contains the term 'diabetes'.
The best way to prepare for a SQL interview, besides making sure you have strong SQL fundamentals, is to practice a ton of real SQL questions that were asked in recent job interviews. In addition to solving the above Option Care Health SQL interview questions, you should also solve the 200+ DataLemur SQL Interview Questions which come from companies like Google, Uber, and Microsoft.
Each interview question has hints to guide you, step-by-step solutions and most importantly, there's an online SQL coding environment so you can instantly run your SQL query and have it executed.
To prep for the Option Care Health SQL interview it is also a great idea to solve SQL questions from other healthcare and pharmaceutical companies like:
But if your SQL query skills are weak, don't worry about going right into solving questions – refresh your SQL knowledge with this DataLemur SQL tutorial.
This tutorial covers SQL concepts such as manipulating date/time data and creating summary stats with GROUP BY – both of which pop up routinely in SQL interviews at Option Care Health.
In addition to SQL interview questions, the other types of problems to prepare for the Option Care Health Data Science Interview include:
To prepare for Option Care Health Data Science interviews read the book Ace the Data Science Interview because it's got:
Also focus on the behavioral interview – prepare for that with this list of common Data Scientist behavioral interview questions.